使用python编写脚本获取手机当前应用apk的信息

import os 
import tempfile 
import re 

tempFile = tempfile.gettempdir() 

def get_aapt(): 
if "ANDROID_HOME" in os.environ: 
rootDir = os.path.join(os.environ["ANDROID_HOME"], "build-tools") 
for path, subdir, files in os.walk(rootDir): 
if "aapt.exe" in files: 
return os.path.join(path, "aapt.exe") 
else: 
return "ANDROID_HOME not exist" 

def get_current_package_name(): 
pattern = re.compile(r"[a-zA-Z0-9.]+/.[a-zA-Z0-9.]+") 
os.popen("adb wait-for-device") 
out = os.popen("adb shell dumpsys input | findstr FocusedApplication").read() 
package_name = pattern.findall(out)[0].split("/")[0] 

return package_name 

def get_match_apk(package_name): 
list = [] 
for packages in os.popen("adb shell pm list packages -f " + package_name).readlines(): 
list.append(packages.split(":")[-1].split("=")[0]) 
apk_name = list[0].split("/")[-1] 
os.popen("adb pull " + list[0] + " " + tempFile) 

return tempFile + "\" + apk_name 

if __name__ == "__main__": 
os.popen(get_aapt() + 
" dump badging " + 
get_match_apk(get_current_package_name()) + 
" > PackageInfo.txt") 
os.popen("del " + tempFile + "\*.apk")